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1839 - 1918 (79 years)
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Name |
Christian S Shantz [1, 2, 3] |
Birth |
21 Aug 1839 |
Waterloo, Ontario, Canada [1, 2, 3] |
Gender |
Male |
Family Search ID |
LQ58-1SY |
Burial |
1918 |
Elkhart, Elkhart, Indiana, USA [1, 3] |
Death |
13 Dec 1918 [1, 2, 3] |
Person ID |
I21119 |
Woodworth Ancestry | Gottlieb Mauck Family |
Last Modified |
7 Jan 2024 |
Family |
Elizabeth Harshbarger, b. 10 Mar 1839, Mount Crawford, Rockingham, Virginia, USA d. 25 Sep 1911 (Age 72 years) |
Marriage |
22 Nov 1866 [2] |
Children |
+ | 1. Charlie Allen Shantz, b. 2 Feb 1868 d. 23 Feb 1957 (Age 89 years) [Father: natural] |
| 2. Minnie Ann Horning, b. 5 Sep 1869 d. 21 Apr 1952 (Age 82 years) [Father: natural] |
| 3. Jesse Hoover Shantz, b. 18 Aug 1871 d. 24 Aug 1872, Champaign County, Illinois, USA (Age 1 year) [Father: natural] |
| 4. Harvey Aldine Shantz, b. 11 Jun 1873 d. 24 Apr 1875 (Age 1 year) [Father: natural] |
| 5. James Milton Shantz, b. 21 Feb 1875 d. 13 Jan 1918 (Age 42 years) [Father: natural] |
| 6. Fannie Elizabeth Shantz, b. 19 Jul 1877 d. 7 Nov 1878, Livingston County, Illinois, USA (Age 1 year) [Father: natural] |
| 7. Cora Alice Linhoss, b. 7 Sep 1879 d. 17 Jan 1967 (Age 87 years) [Father: natural] |
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Family ID |
F11354 |
Group Sheet | Family Chart |
Last Modified |
7 Jan 2024 |
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Sources |
- [S198] Ancestry.com, U.S., Find A Grave Index, 1600s-Current, (Name: Ancestry.com Operations, Inc.; Location: Provo, UT, USA; Date: 2012;).
Record for Elizabeth M Shantz
https://search.ancestry.com/cgi-bin/sse.dll?db=60525&h=93389419&indiv=try
- [S678] Ancestry.com, Lancaster, Pennsylvania, Mennonite Vital Records, 1750-2014, (Name: Ancestry.com Operations, Inc.; Location: Provo, UT, USA; Date: 2015;).
Record for Christian S. Shantz
https://search.ancestry.com/cgi-bin/sse.dll?db=60592&h=719903&indiv=try
- [S198] Ancestry.com, U.S., Find A Grave Index, 1600s-Current, (Name: Ancestry.com Operations, Inc.; Location: Provo, UT, USA; Date: 2012;).
Record for Charlie Allen Shantz
https://search.ancestry.com/cgi-bin/sse.dll?db=60525&h=93389505&indiv=try
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